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3 Commits

Author SHA1 Message Date
steven 4843a4fffc feat(solution): problem #10 2023-07-31 14:22:13 -04:00
steven 237c116253 feat(solution): problem #9 2023-07-31 14:17:27 -04:00
steven 4570c7b66f feat(solution): problem #8 2023-07-31 14:06:52 -04:00
3 changed files with 53 additions and 0 deletions

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bigNumberString = str(7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450)
biggestProduct = 0
numberOfAdjacentDigits = 13
for i in range(0, len(bigNumberString) - numberOfAdjacentDigits):
currentProduct = int(bigNumberString[i])
for j in range(1, numberOfAdjacentDigits):
currentProduct *= int(bigNumberString[i+j])
if currentProduct > biggestProduct:
biggestProduct = currentProduct
print("The greatest product of thirteen adjacent digits is: " + str(biggestProduct))

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def is_pythagorean_triplet(a, b, c):
if (a * a + b * b) == (c * c):
return True
else:
return False
tripletFound = False
for i in range(1,500):
for j in range(1,500):
for k in range(1,500):
if is_pythagorean_triplet(i, j, k):
print("triplet:",i,j,k)
if i+j+k == 1000:
print("The product of abc is: " + str(i*j*k))
tripletFound = True
if tripletFound:
break
if tripletFound:
break
if tripletFound:
break

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import math
primeSum = 0
currentNumber = 1
limit = 2000000
def is_prime(maybeprime):
for i in range(2, math.floor(math.sqrt(maybeprime) + 1)):
if maybeprime % i == 0:
return False
return True
while currentNumber < limit:
currentNumber += 1
if is_prime(currentNumber):
primeSum += currentNumber
print("The sum of all primes below two million is: " + str(primeSum))