feat(solution): problem #17

solutions/017/numberlettercounts.py

@@ -0,0 +1,73 @@
+numberWord = {
+    0: '',
+
+    1: 'one', 
+    2: 'two', 
+    3: 'three', 
+    4: 'four', 
+    5: 'five', 
+    6: 'six', 
+    7: 'seven', 
+    8: 'eight', 
+    9: 'nine', 
+    
+    10: 'ten', 
+    11: 'eleven', 
+    12: 'twelve', 
+    13: 'thirteen', 
+    14: 'fourteen', 
+    15: 'fifteen', 
+    16: 'sixteen', 
+    17: 'seventeen', 
+    18: 'eighteen', 
+    19: 'nineteen', 
+    
+    20: 'twenty', 
+    30: 'thirty', 
+    40: 'forty', 
+    50: 'fifty', 
+    60: 'sixty', 
+    70: 'seventy', 
+    80: 'eighty', 
+    90: 'ninety',
+
+    100: 'onehundred',
+    200: 'twohundred',
+    300: 'threehundred',
+    400: 'fourhundred',
+    500: 'fivehundred',
+    600: 'sixhundred',
+    700: 'sevenhundred',
+    800: 'eighthundred',
+    900: 'ninehundred',
+
+    1000: 'onethousand'
+}
+andString = "and"
+
+numberString = ""
+
+for i in range (1,21):
+    numberString += numberWord[i]
+
+for i in range (21,1001):
+    ones = i % 10
+    tens = i % 100 - ones
+    huns = i - tens - ones
+
+    numberStringInProgress = ""
+
+    if i == 20 or i == 30 or i == 40 or i == 50 or i == 60 or i == 70 or i == 80 or i == 90 or i == 100 or i == 200 or i == 300 or i == 400 or i == 500 or i == 600 or i == 700 or i == 800 or i == 900 or i == 1000:
+        numberString += numberWord[i]
+    else:
+        if i > 100:
+            numberStringInProgress += numberWord[huns]
+            numberStringInProgress += andString
+        if tens >= 20 or tens == 0:
+            numberStringInProgress += numberWord[tens]
+            numberStringInProgress += numberWord[ones]
+        elif tens == 10:
+            numberStringInProgress += numberWord[tens+ones]
+        numberString += numberStringInProgress
+
+print("The length of all the numbers from 1 to 1000 (inclusive) written out in words is " + str(len(numberString)) + " letters.")